9x^2=258

Solution for 9x^2=258 equation:

9x^2=258

We move all terms to the left:

9x^2-(258)=0

a = 9; b = 0; c = -258;
Δ = b2-4ac
Δ = 02-4·9·(-258)
Δ = 9288
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9288}=\sqrt{36*258}=\sqrt{36}*\sqrt{258}=6\sqrt{258}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{258}}{2*9}=\frac{0-6\sqrt{258}}{18}
=-\frac{6\sqrt{258}}{18}
=-\frac{\sqrt{258}}{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{258}}{2*9}=\frac{0+6\sqrt{258}}{18}
=\frac{6\sqrt{258}}{18}
=\frac{\sqrt{258}}{3}
$